Envision Math 2.0: Grade 8, Volume 1
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3. Compare and Order Real Numbers
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Exercise 15 Page 24

Practice makes perfect

We are given a rectangle that has an area of 90 square units and a length that is twice the width.

Rectangle in one piece
As was said, we can divide it into two squares. To do this we will connect the halves of the longer sides of the given rectangle.
Rectangle divided into two squares

This results in two identical squares whose areas are 45 square units each.

Rectangle divided into two squares
To find the length of the side of the resulting square, we will use the formula for the area of a square. A=s^2 Let's find the length of the side s by substituting 45 for A.
A=s^2
45=s^2
Solve for s
sqrt(45)=sqrt(s^2)
sqrt(45)=s
s=sqrt(45)
Each side of squares is sqrt(45) units long.
From Part A we know that the width of the rectangle is sqrt(45) units. We will estimate it to the nearest tenth by finding consecutive perfect squares around the number under the root. The two nearest perfect squares are 36 and 49.
36<45<49
sqrt(36)
6

We know that sqrt(45) is somewhere between 6 and 7. To approximate it to the nearest tenth we will use decimals between 6 and 7. Let's calculate the square of each number and compare them with 45.

Approximation Square of Approximation Comparison
6.1 6.1 * 6.1 = 37.21 Approximation is too low
6.2 6.2 * 6.2 = 38.44 Approximation is too low
6.3 6.3 * 6.3 = 39.69 Approximation is too low
6.4 6.4 * 6.4 = 40.96 Approximation is too low
6.5 6.5 * 6.5 = 42.25 Approximation is too low
6.6 6.6 * 6.6 = 43.56 Approximation is too low
6.7 6.7 * 6.7 = 44.89 Approximation is too low
6.8 6.8 * 6.8 = 46.24 Approximation is too high

We know that sqrt(45) is somewhere between 6.7 and 6.8. In order to estimate it to the nearest tenth, we need to find which square is closer. We will do this by finding the difference between 44.89 and 45, and 45 and 46.24. 45.89-0.11 ←45+1.24 →46.24 Because 45 is closer to 44.89, we know that sqrt(45) is closer to sqrt(44.89). Therefore, the nearest decimal number to sqrt(45) is 6.7. Since the length of the rectangle is twice its width, it will measure 2sqrt(45) units. We can estimate it to 13.4 units using the approximation of sqrt(45).