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If two quantities are related and one of them varies, then the other quantity will also vary. Depending on the type of relationship they have, the second quantity will vary in a specific way. This lesson will explore the ideas of direct variation and proportional relationships.

### Catch-Up and Review

Here are a few recommended readings before getting started with this lesson.

Here are a few practice exercises before getting started with this lesson.

a Consider the table of values.
A
B
C

Find the values of A, B, and C.

b Consider the table of values.

Consider now the following graphs.  Which of the graphs corresponds to the table?

## Moving a Point Along a Line

Consider the following line through the origin. For any point on this line, the ratio of its coordinate to its coordinate is always the same. Does this happen for every line through the origin?

## Direct Variation

Direct variation, also known as direct proportionality or proportional relationship, occurs when two variables, and have a relationship that forms a linear function passing through the origin where and

The constant is the constant of variation. It defines the slope of the line. When the relationship is not in direct variation. In the example below, the constant of variation is The constant of variation may be any real number except It is worth noting that the quotient of and is the constant of variation.

## Graphing a Direct Variation

Paulina is selling lemonade to save some money for her summer vacation. For each glass of lemonade she sells, Paulina makes a profit of She models this situation with a direct variation.
Here, is the profit made when glasses are sold. Also, is the constant of variation.
a Consider the following graphs.  Which of the graphs corresponds to the given direct variation?
b What is Paulina's profit if she sells glasses?

### Hint

a Draw the graph of the direct variation and compare it with the given graphs.
b Use the graph from Part A.

### Solution

a To determine which of the four graphs represents the given direct variation, the graph of will be drawn by making a table of values.
Now, the obtained points in the table will be plotted and connected with a straight line. The obtained graph is the same as Graph II. Note that in the context of the situation, negative values of do not make sense, since Paulina cannot sell a negative number of glasses of lemonade.
b To calculate Paulina's profit when selling glasses of lemonade, the graph from Part A will be used. The profit for glasses is Note that this can be verified using the equation. To do so, will be substituted for

## Writing a Direct Variation

Tadeo is given the following math homework. ### Hint

The general form of a direct variation is where is the constant of variation.

### Solution

Start by writing the general form of a direct variation.
Here, is the constant of variation. To find its value, and will be substituted into the equation.
Solve for
The constant of variation is With this information, the equation can be written.
Finally, this equation can be used to find the value of when
Evaluate right-hand side
When the value of is

## Writing a Direct Variation Knowing a Point

Tearrik is given the graph of a direct variation and one of its points. To complete his homework before going dancing, he wants to find the equation of the direct variation shown in the graph. Help him do this!

### Hint

The equation of a direct variation is where is the constant of variation.

### Solution

Start by recalling the general form of a direct variation.
Here, is the constant of variation. To find its value, the point will be used. To do this, and will be substituted into the above equation.
Solve for
The constant of variation is With this information, the formula can be written.

## Writing a Direct Variation Knowing Its Graph

This time, Tearrik is given the graph of a direct variation, but none of its points are plotted. Once again, to complete his homework before going dancing, he wants to find the equation of the direct variation shown in the graph. Help him do this!

### Hint

Use any point on the line.

### Solution

Recall the general form of a direct variation.
Here, is the constant of variation. To find its value, any point on the given graph can be used. For simplicity, the point will be considered. To find the constant of variation, and will be substituted into the general formula.
Solve for
The constant of variation is With this information, the equation of the direct variation of the given graph can be written.

## Finding the Constant of Variation

Find the constant of variation of the direct variation whose graph is given. If the answer is not an integer, write it as a decimal rounded to one decimal place. ## Modeling With Direct Variation

Tiffaniqua is jogging on Saturday morning. As she jogs, Tiffaniqua keeps a constant speed of a Let represent the distance in kilometers and the time in hours. Write a direct variation in terms of and to represent this situation.
b Consider the following graphs.  Which of these is the graph of the direct variation from Part A?
c How many kilometers would Tiffaniqua travel in minutes?
How many hours would it take her to travel kilometers?
d How many kilometers would Tiffaniqua travel in hours and minutes?
How many hours will it take her to travel kilometers?

### Hint

a What is the constant of variation?
b If Tiffaniqua's speed is then she travels kilometers in one hour.
c Use the graph from Part B.
d Use the formula from Part A.

### Solution

a The distance traveled varies directly with the time Since Tiffaniqua's speed is the constant of variation is
b The graph of a direct variation passes through the origin. Therefore, the point is on the graph of To find another point on the line, any value can be substituted for in the formula. For simplicity, will be used.
It has been found that the point is also on the line. To draw the graph, these two points will be plotted and the line through them will be drawn. This graph corresponds to Graph III. Note that in the context of the situation, a negative value of does not make sense, since Tiffaniqua cannot run for a negative amount of hours.
c To find how many kilometers Tiffaniqua would travel in minutes and how many hours it would take her to travel kilometers, the graph from Part B will be used. It can be seen that, if Tiffaniqua jogged at a constant speed of kilometers per hour, she would travel kilometers in minutes. Similarly, it would take her one and a half hours to travel kilometers.
d Since these two values are too large to be seen in the graph, the formula from Part A will be used.
Recall that is the distance in kilometers and the time in hours. To find how many kilometers Tiffaniqua would travel in hours and minutes, minutes need to be expressed in hours.
Therefore, hours and minutes are hours. This value can be substituted for in the equation.
In hours and minutes, Tiffaniqua would travel kilometers. Finally, to calculate how many hours it would take her to travel kilometers at this speed, will be substituted for in the formula.
If she kept her constant speed, it would take Tiffaniqua hours to travel kilometers.

## Inverse Variation

Another type of variation is inverse variation. Here, one variable is the quotient of the constant of variation and the other variable, which cannot be zero.
Inverse variation occurs when the product of the variables is constant.
As in direct variation, the constant of variation cannot be zero. For example, let the constant of variation of an inverse variation be To draw its graph, a table of values will be first made. Only positive values will be considered for the variable.
Next, the points found in the table will be plotted and connected. The graph of an inverse variation is not a straight line.
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