Notice that x=3 goes through B. This means we only have to reflect A. To do that, we draw a perpendicular segment from A to x=3. By extending this segment until its congruent with the first segment, we will have found the location of the reflected point.
Finally, we connect all three points to form â–ł A'BA.
b Let's first plot the line into the same coordinate plane as AB. Notice that the line is given in slope-intercept form which means we can identify its slope and y-intercept.
|c|c|c|
Equation & m & b
y= -x+ 6 & -1 & 6
To graph a line we need to know at least two points on the graph. The first point we will mark is the line's y-intercept. By using the line's slope we can find a second point which then allows us to draw the line.
Like in Part A, we draw perpendicular segments from A and B to the line of reflection and then extend those on the opposite side of the line until they are congruent with the corresponding first segments.
