Core Connections Geometry, 2013
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Core Connections Geometry, 2013 View details
1. Section 2.1
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Exercise 31 Page 96

Practice makes perfect
a The equations are given in slope-intercept form.
y=mx+b Here, m is the slope and b is the y-intercept. We see that the first equation has the slope m= -1 and a y-intercept of b= 1.

y= -1 x+ 1 We can then draw the first line by plotting the y-intercept before using the slope to find a second point. We can then draw a line through the points to form the line.

We do the same thing with the second equation which has a slope of m= 2 and a y-intercept at b= 7.

We can then see the point of intersection between the lines.

The intersection is located at (-2,3).

b
We can solve the system of equation by using the Substitution Method. As the equations are both solved for one variable, we can insert either one into the other. y=- x+1 & (I) y=2x+7 & (II)We choose to substitute the y from (I) into (II).
y=- x+1 y=2x+7
â–Ľ
Solve by substitution
y=- x+1 - x +1=2x+7
y=- x+1 1=3x+7
y=- x+1 -6=3x
y=- x+1 3x=-6
y=- x+1 x=-2
We have found that x=-2. We can then substitute this back in to the fist equation to solve for y.
y=- x+1 x=-2
y=- ( -2)+1 x=-2
y=2+1 x=-2
y=3 x=-2
We have then found that the point of intersection is (-2,3). Which is the same answer as in part A.