Core Connections Geometry, 2013
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Core Connections Geometry, 2013 View details
1. Section 2.1
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Exercise 58 Page 106

Practice makes perfect
a To graph the line y= 34x, we can use the fact that it is written in slope-intercept form. This means we can find the slope and y-intercept.
|c|c|c| Function & m & b [-0.8em] y= 3/4x& 3/4 & 0 [0.8em]

To graph the line we need to know at least two points through which it passes. We know that it's y-intercept is 0. Therefore, it passes through the origin. Using the slope, we can find one more point on the line and then draw it.

Let's isolate the slope triangle.

b To rotate the slope triangle about the origin, we place a protractor along the hypotenuse of the slope triangle and then draw a second segment along the 90^(∘) mark that is congruent with the hypotenuse.

We also have to rotate the vertex at the 90^(∘) angle.

Now we can draw the rotated slope triangle and mark the side's length.

As we can see, the new slope is m= -43.

c A line perpendicular to y= 43x has to have a slope that is the negative reciprocal of 43. This means the product of their slopes equals -1.
m_1 m_2=-1By substituting m_1= 43 into the formula, we can find the slope of the perpendicular line.
m_1 m_2=-1
( 4/3)m_2=-1
Solve for m_2
4m_2=-3
m_2=-3/4
The slope of the perpendicular line to y= 43x is m=- 34 Notice that we are free to choose whatever y-intercept we want. Therefore, we will keep it simple and choose the origin. y=- 3/4x+0 ⇔ y=- 3/4x