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Substitute values
- (- a)=a
(- a)^2 = a^2
Multiply
Subtract term
Use a calculator
k ≈ 15± 7.55/6 | |
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k_1 ≈ 15+ 7.55/6 | k_2 ≈ 15- 7.55/6 |
k_1 ≈ 22.55/6 | k_2 ≈ 6.69/6 |
k_1 ≈ 3.76 | k_2 ≈ 1.24 |
Using the Quadratic Formula, we found that the solutions of the given equation are k_1 ≈ 3.76 and k_2 ≈ 1.24.
Absolute Value Inequality:& |x-4| < 6 Compound Inequality:& - 6< x-4 < 6 We can split this compound inequality into two cases — one where x-4 is greater than -6 and one where x-4 is less than 6. x-4>- 6 and x-4 < 6 Let's isolate x in both of these cases before graphing the solution set.
LHS+4
The solution to this type of compound inequality is the overlap of the solution sets. Let's recombine our cases back into one compound inequality. First Solution Set:& x < 10 Second Solution Set:& - 2 < x Intersecting Solution Set:& - 2 < x < 10
LHS+1=RHS+1
LHS-3x=RHS-3x
Rearrange equation
.LHS /3.=.RHS /3.