Core Connections Algebra 1, 2013
CC
Core Connections Algebra 1, 2013 View details
1. Section 11.1
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Exercise 10 Page 528

Practice makes perfect
a Using the function f(x), we want to find the expression f(x)+2. To do this, we will add 2 to the given function and simplify.
f(x)=x^2-3
f(x)+ 2=x^2-3+ 2
f(x)+2=x^2-1
We can describe this transformation as vertical translation 2 units up. It means that the graph of the given function was shifted 2 units up.
b Using the function f(x), we want to find the expression 2 * f(x). To do this, we will multiply the given function by 2 and simplify.
f(x)=x^2-3
2 * f(x)= 2(x^2-3)
2 * f(x)=2x^2-6
We can describe this transformation as vertical stretch by a factor of 2.
c Using the function f(x), we want to evaluate for the given value, f( x+2). To do this, we need to substitute x+2 for x in each instance of the x-variable.
f(x)=x^2-3
f( x+2)=( x+2)^2-3
We can describe this transformation as horizontal translation 2 units left. It means that the graph of the given function was shifted 2 units left.
d Using the function f(x), we want to evaluate for the given value, f( 2x). To do this, we need to substitute 2x for x in each instance of the x-variable and simplify.
f(x)=x^2-3
f( 2x)=( 2x)^2-3
f(2x)=2^2x^2-3
f(2x)=4x^2-3
We can describe this transformation as horizontal stretch by a factor of 2.