Exercise 5 Page 183

Gather all of the variable terms on one side of the equation and all of the constant terms on the other side.

x=4

Practice makes perfect

To solve an equation, we should first gather all of the variable terms on one side and all of the constant terms on the other side using the Properties of Equality.

0.1x-1=1.2x-5.4

SubEqn

LHS-1.2x=RHS-1.2x

0.1x-1-1.2x=1.2x-5.4-1.2x

SubTerms

Subtract terms

-1.1x-1=-5.4

Now, we can continue to solve using the Properties of Equality.

-1.1x-1=-5.4

AddEqn

LHS+1=RHS+1

-1.1x-1+1=-5.4+1

AddTerms

Add terms

-1.1x=-4.4

MultEqn

LHS * (-1)=RHS* (-1)

-1(-1.1x)=-1(-4.4)

MultPropNegOne

Multiplication Property of -1

1.1x=4.4

DivEqn

.LHS /1.1.=.RHS /1.1.

1.1x/1.1=4.4/1.1

MovePartNumRight

a* b/c=a/c* b

1.1/1.1 * x=4.4/1.1

CalcQuot

Calculate quotient

1 * x=4

IdPropMult

Identity Property of Multiplication

x=4

The solution to the equation is x=4. We can check our solution by substituting it into the original equation.

0.1x-1=1.2x-5.4

Substitute

x= 4

0.1( 4)-1 ? = 1.2( 4)-5.4

Multiply

0.4-1 ? = 4.8-5.4

SubTerms

Subtract terms

-0.6 = -0.6 ✓

Since the left-hand side is equal to the right-hand side, our solution is correct.

Subchapter links

Try It p.180-181

Self-Assessment for Concepts & Skills p.181

Self-Assessment for Problem Solving p.182

Review & Refresh p.183

Concepts, Skills, & Problem Solving p.183-184

Exercise 5 Page 183

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