Big Ideas Math: Modeling Real Life, Grade 8
BI
Big Ideas Math: Modeling Real Life, Grade 8 View details
4. Surface Areas and Volumes of Similar Solids
Continue to next subchapter

Exercise 19 Page 451

When two solids are similar the ratio of their volumes is equal to the ratio of their corresponding linear measures cubed.

13 564.8 cubic feet

Practice makes perfect

We know the radius of base of two similar cylinders but the volume of just one of them.

prisms
When two solids are similar, the ratio of their volumes is equal to the ratio of their corresponding linear measures cubed. Volume of the smaller solid/Volume of the bigger solid = (Radius of the smaller solid/Radius of the bigger solid)^3 We know that the radius and the volume of the smaller solid are 10 feet and 7850 cubic feet, respectively. We also know that the radius of the bigger solid is 12 feet. If we let V be the volume of the bigger solid, we can substitute these values in this equation and solve for V.
Volume of the smaller solid/Volume of the bigger solid=(Radius of the smaller solid/Radius of the bigger solid)^3
7850/V=(10/12)^3
â–Ľ
Solve for V
7850/V=(5/6)^3
7850/V=5^3/6^3
7850/V=125/216
7850=125/216 * V
7850=125V/216
7850 * 216=125V
1 695 600=125V
1 695 600/125=V
13 564.8=V
V=13 564.8
The volume of the bigger cylinder is 13 564.8 cubic feet.