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When two solids are similar, the ratio of their surface areas is equal to the ratio of their corresponding linear measures squared, and the ratio of their volumes is equal to the ratio of their corresponding linear measures cubed.
Surface Area: 52yd^2
Volume: 24yd^3
We know the heights of two similar rectangular prisms but the surface area and volume of just one of them.
We will use the knowledge that these prisms are similar to find the suface area and volume of the bigger solid. We will do these things one at a time.
When two solids are similar, the ratio of their surface areas is equal to the ratio of their corresponding linear measures squared.
Substitute values
a/b=.a /2./.b /2.
(a/b)^m=a^m/b^m
LHS * S=RHS* S
LHS * 4=RHS* 4
Rearrange equation
The surface area of the bigger rectangular prism is 52 square yards.
When two solids are similar, the ratio of their volumes is equal to the ratio of their corresponding linear measures cubed. Volume of the smaller solid/Volume of the bigger solid = (Height of the smaller solid/Height of the bigger solid)^3 We know that the height and the volume of the smaller solid are 2 yards and 3 cubic yards, respectively. We also know that the height of the bigger solid is 4 yards. If we let V be the volume of the bigger solid, we can substitute these values in this equation and solve for V.
Substitute values
a/b=.a /2./.b /2.
(a/b)^m=a^m/b^m
LHS * V=RHS* V
LHS * 8=RHS* 8
Rearrange equation
The volume of the bigger rectangular prism is 24 cubic yards.