Big Ideas Math: Modeling Real Life, Grade 8
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Big Ideas Math: Modeling Real Life, Grade 8 View details
4. Surface Areas and Volumes of Similar Solids
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Exercise 11 Page 451

Similar solids are solids that have the same shape and proportional corresponding dimensions.

d=2.5 feet

Practice makes perfect

We know that a cylinder with a diameter of 10 feet and a height of 4 feet is similar to a cylinder with a diameter of d feet and a height of 1 feet.

We want to find the value of d. Recall that similar solids are solids that have the same shape and proportional corresponding dimensions. Therefore, the ratio between corresponding dimensions is constant. We can use this information to write a proportion. Diameter of the bigger cylinder/Diameter of the smaller cylinder = Height of the bigger cylinder/Height of the smaller cylinder Let's substitute the corresponding dimensions into this equation and solve for r.

Diameter of the bigger cylinder/Diameter of the smaller cylinder=Height of the bigger cylinder/Height of the smaller cylinder
10/d=4/1
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Solve for d
10/d=4
10=4d
10/4=d
d=10/4
d=2.5

The diameter of the smaller cylinder d is 2.5 feet long.