Big Ideas Math: Modeling Real Life, Grade 8
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Big Ideas Math: Modeling Real Life, Grade 8 View details
4. Surface Areas and Volumes of Similar Solids
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Exercise 15 Page 451

When two solids are similar, the ratio of their surface areas is equal to the ratio of their corresponding linear measures squared.

90 square meters

Practice makes perfect

We know the heights of two similar rectangular prisms but the surface area of just one of them.

prisms
When two solids are similar, the ratio of their surface areas is equal to the ratio of their corresponding linear measures squared. Surface area of the smaller solid/Surface area of the bigger solid = (Length of the smaller solid/Length of the bigger solid)^2 We know that the length and the surface area of the smaller solid are 4 meters and 40 square meters, respectively. We also know that the length of the bigger solid is 6 meters. If we let S be the surface area of the bigger solid, we can substitute these values into this equation and solve for S.
Surface area of the smaller solid/Surface area of the bigger solid=(Length of the smaller solid/Length of the bigger solid)^2
40/S=(4/6)^2
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Solve for S
40/S=(2/3)^2
40/S=2^2/3^2
40/S=4/9
40=4/9S
40=4S/9
40 * 9=4S
360=4S
360/4=S
S=360/4
S=90
The surface area of the bigger rectangular prism is 90 square meters.