Big Ideas Math: Modeling Real Life, Grade 8
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Big Ideas Math: Modeling Real Life, Grade 8 View details
4. Surface Areas and Volumes of Similar Solids
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Exercise 16 Page 451

When two solids are similar, the ratio of their surface areas is equal to the ratio of their corresponding linear measures squared.

2827.7 square inches

Practice makes perfect

We know the heights of two similar spheres but the surface area of just one of them.

prisms
When two solids are similar, the ratio of their surface areas is equal to the ratio of their corresponding linear measures squared. Surface area of the smaller sphere/Surface area of the bigger sphere = (Radius of the smaller sphere/Radius of the bigger sphere)^2 We know that the radius and the surface area of the bigger sphere are 20 inches and 5027 square inches, respectively. We also know that the radius of the smaller solid is 15 inches. If we let S be the surface area of the smaller solid, we can substitute these values into the equation and solve for S.
Surface area of the smaller sphere/Surface area of the bigger sphere=(Radius of the smaller sphere/Radius of the bigger sphere)^2
S/5027=(15/20)^2
Solve for S
S/5027=(3/4)^2
S/5027=3^2/4^2
S/5027=9/16
S=9/16 * 5027
S=9 * 5027/16
S=45 243/16
S=2827.6875
S ≈ 2827.7
The surface area of the smaller sphere is about 2827.7 square inches.