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Prove: RM=CD
We can now use these labels to write the given information about the lengths. Given:& RS= CF, & SM= MC= FD We are asked to prove that the distance from the restaurant to the movie theater RM is the same as the distance from the cafe to the dry cleaners CD. Prove: RM=CD
Statement1)& RS= CF, & SM= MC= FD Reason1)& Given Since points R, S, and M are collinear and S is between R and M, we can use the Segment Addition Postulate. We can do the same for points C, F, and D.
This will be our second statement. Statement& 2) RM= RS+SM, & CD=CF+FD Reason& 2) Segment Addition Postulate We are given that RS= CF and SM= FD. By the Substitution Property of Equality, we can substitute RS and SM for CF and FD, respectively, in the diagram.
Therefore, CD is the sum of RS and SM. This is our third statement. Statement& 3) CD=RS+SM Reason& 3) Substitution Property & of Equality Now we have that both RM and CD are equal to RS+ SM. This means that, by the Transitive Property of Equality, RM is equal to CD. Statement& 4) RM=CD Reason& 4) Transitive Property & of Equality Let's write this as a two-column proof!
Statement
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Reason
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1. RS = CF, SM=MC=FD
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1. Given
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2. RM=RS+SM, CD=CF+FD
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2. Segment Addition Postulate
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3. CD=RS+SM
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3. Substitution Property of Equality
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4. RM=CD
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4. Transitive Property of Equality
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