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The slopes of parallel lines are the same. Therefore, to find the slope of a parallel line, we need to know the slope of the given line. Let's calculate it by substituting the points that lie on the given line into the Slope Formula.
The slope of the given line and, consequently, of the parallel line is 3. We can write a partial equation of our line recalling the slope-intercept form. y= mx+b ⇓ y= 3x+b Next, by substituting the given point ( 6, 2) in the above equation, we can find the y-intercept b.
Now that we know that b = -16, we can write the equation of our line. y=3x + ( -16) ⇒ y = 3x - 16
m_1* m_2=- 1
From Part A, we know that the slope of the given line is 3. We can substitute 3 for m_2 into the above equation to find m_1, the slope of the perpendicular line.
The slope of the perpendicular line is - 13. We can write its partial equation recalling the slope-intercept form. y= mx+b ↓ y= -1/3x+b Next, by substituting the given point ( 6, 2) in the above equation, we can find the y-intercept b.
x= 6, y= 2
a/c* b = a* b/c
Multiply
Calculate quotient
LHS+2=RHS+2
Rearrange equation
Now that we know that b= 4, we can write the equation of our line. y=-1/3x+ 4