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Point-slope form is y-y_1=m(x-x_1).
f(x)=- 6
Let's start by expressing f(-1)=-6 as (-1,-6), and f(4)=- 6 as (4,- 6). Equations in point-slope form follow a specific format.
y- y_1= m(x- x_1)
In this form, m is the slope of the line and ( x_1, y_1) is a point on the line. Here, we are given that the line passes through two known points.
Substitute ( - 1,-6) & ( 4,- 6)
a-(- b)=a+b
Add terms
Calculate quotient
Now that we know the slope of the line is 0, we can write the equation of the line in point-slope form. We can use either of the given points as (x_1,y_1) in our equation. Let's use ( - 1, -6).
Substitute values
Zero Property of Multiplication
a-(- b)=a+b
LHS-6=RHS-6
Now, we can write the equation in terms of f(x). f(x) = - 6 Please note that if we substitute any point of the line into the point-slope equation, we will get the same answer, since the slope is 0.