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Point-slope form is y-y_1=m(x-x_1).
Example Solution: y+2=5(x+3)
Let's start by expressing f(-3) = -2 as (-3,-2) and f(-2)=3 as (-2,3). Equations in point-slope form follow a specific format.
y- y_1= m(x- x_1)
In this form, m is the slope of the line and ( x_1, y_1) is a point on the line. Here, we are given that the line passes through two known points.
Substitute ( -3,-2) & ( -2,3)
a-(- b)=a+b
Add and subtract terms
a/1=a
Now that we know the slope of the line is 5, we can write the equation of the line in point-slope form. We can use either of the given points as (x_1,y_1) in our equation. Let's use ( - 3, - 2).
Please note that any point on the line can be used to form a point-slope equation. Therefore, our equation is only one of infinitely many possible equations!