Big Ideas Math Integrated I, 2016
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Big Ideas Math Integrated I, 2016 View details
1-3. Quiz
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Exercise 9 Page 184

Point-slope form is y-y_1=m(x-x_1).

Example Solution: y+2=5(x+3)

Practice makes perfect

Let's start by expressing f(-3) = -2 as (-3,-2) and f(-2)=3 as (-2,3). Equations in point-slope form follow a specific format. y- y_1= m(x- x_1) In this form, m is the slope of the line and ( x_1, y_1) is a point on the line. Here, we are given that the line passes through two known points. (- 3,-2) and (-2, 3) To determine the slope of the line, we use the Slope Formula.

m=y_2-y_1/x_2-x_1
m=3-( -2)/-2-( -3)
m=3+2/-2+3
m=5/1
m=5

Now that we know the slope of the line is 5, we can write the equation of the line in point-slope form. We can use either of the given points as (x_1,y_1) in our equation. Let's use ( - 3, - 2).

y-y_1=m(x-x_1)
y-( -2)= 5(x-( -3))
y+2=5(x+3)

Please note that any point on the line can be used to form a point-slope equation. Therefore, our equation is only one of infinitely many possible equations!