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Big Ideas Math Integrated I, 2016

BI

Big Ideas Math Integrated I, 2016 View details

3. Solving Inequalities Using Multiplication or Division

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Exercise 37 Page 72

Substitute r= C2π into the inequality in the given diagram and solve for C.

Inequality: C/2π>5
Solution: C > 10π

Practice makes perfect

We want to determine the possible values for the circumference of a circle whose radius is greater than 5.

To do so, we will consider the formula for the radius r in terms of the circumference C. r = C/2π Now, we will substitute C2π for r in the inequality given in the diagram, r>5. r>5 ⇒ C/2π>5 Finally, we will use inverse operations to isolate C.

C/2π > 5

LHS* 2π > RHS * 2π

C> 10π

A circle with a radius greater than 5 will have a circumference that is greater than 10π.

Subchapter links

Communicate Your Answer p.67

Monitoring Progress p.68-70

Exercises p.71-72