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Break down the given absolute value equation into two separate equations.
Solutions: w=-26 and w=-2/3
Graph:
When solving an equation involving absolute value expressions, we should consider what would happen if we removed the absolute value symbols. Let's look at an example equation. |ax+b|=|cx+d| Although we can make 4 statements about this equation, there are actually only two possible cases to consider.
Statement | Result |
---|---|
Both absolute values are positive. | ax+b=cx+d |
Both absolute values are negative. | -(ax+b)=-(cx+d) |
Only the left-hand side is negative. | -(ax+b)=cx+d |
Only the right-hand side is negative. | ax+b=-(cx+d) |
Because of the Properties of Equality, when the absolute values of two expressions are equal, either the expressions are equal or the opposites of the expressions are equal. Now let's consider these two cases for the given equation. Given Equation:& |1/2w-6|=|w+7| First Equation:& 1/2w-6 = w+7 Second Equation:& 1/2w-6=- (w+7) These two equations can now be solved by conventional means.
(II): Distribute -1
(I), (II):LHS+6=RHS+6
(I):LHS-w=RHS-w
(I):Subtract term
(I):LHS * (-2)=RHS* (-2)
(II):LHS+w=RHS+w
(II):Add fractions
(II):LHS * 2/3=RHS* 2/3
w= -26
a(- b)=- a * b
Calculate quotient
Add and subtract terms
|-19|=19
w= -2/3
Multiply fractions
a/b=.a /2./.b /2.
a = 3* a/3
Add and subtract terms
|-19/3|=19/3
|19/3|=19/3
The solutions to the given equation are the points w=-26 and w=- 23. In order to graph the solutions, we will plot them on a number line.