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What are the x- and y-coordinates of points on that lie on the y- and x-axis?
Graph:
Right triangle/Isosceles triangle?: Right
Side lengths: DE=m, EF=n, DF=sqrt(m^2+n^2)
Slope: m_(DE)=0, m_(EF)=Undefined, m_(DF)=- nm
Midpoints: M_(DE)( m2,n), M_(EF)(m, n2), M_(DF)( m2, n2)
Any point that's on the x-axis has a y-coordinate of 0. Similarly, any point on the y-axis has an x-coordinate of 0. Therefore, it must be that &F(m, 0) is on the $x-$axis &D( 0,n) is on the $y-$axis. Let's plot these points in a coordinate plane and draw DF.
To find the slope of the sides, we can use the Slope Formula. Note that horizontal lines have a slope of 0 and vertical sides have an undefined slope. Therefore, the only side we need to determine the slope for by using the Slope Formula is DF.
Substitute ( m,0) & ( 0,n)
Subtract terms
Put minus sign in front of fraction
To find the length of the sides, we can use the Distance Formula. However, we do not need to use the formula for the horizontal and vertical sides as their lengths are the absolute value of the difference between the endpoints' x-coordinates and y-coordinates, respectively. DE:& |m-0|=m EF:& |n-0|=n The remaining side, we have to calculate with the Distance Formula.
Substitute ( m,0) & ( 0,n)
Subtract terms
Calculate power
Let's summarize the length and slope: &Slope && Distance &m_(DE)=0 && d_(DE)=m &m_(DF)=- n/m && d_(DF) = sqrt(m^2 + n^2) &m_(EF)=non-existent && d_(EF)=n
To find the midpoint of any side we can use the Midpoint Formula.
| Side | Points | M(x_1+x_2/2,y_1+y_2/2) | Midpoint |
|---|---|---|---|
| DE | ( m,n), ( 0,n) | M(m+ 0/2,n+ n/2) | M(m/2,n) |
| EF | ( m,n), ( m,0) | M(m+ m/2,n+ 0/2) | M(m,n/2) |
| DF | ( m,0), ( 0,n) | M(m+ 0/2,0+ n/2) | M(m/2,n/2) |
Let's summarize the midpoints: M_(DE)(m/2,n), M_(EF)(m,n/2), M_(DF)(m/2,n/2)