Big Ideas Math Geometry, 2014
BI
Big Ideas Math Geometry, 2014 View details
8. Surface Areas and Volumes of Spheres
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Exercise 40 Page 654

Practice makes perfect
a
The Torrid Zone is shaped as a 3250 miles wide cylindrical belt around the Earth. This belt, if displayed flat instead of wrapped around the Earth, has the shape of a rectangle.
Illustration showing the torrid zone as a belt wrapped around the Earth and as a flat strip
To find the area of the Torrid Zone we can use the formula for finding the area of a rectangle. The rectangle's length will then be the circumference of the Earth. A=l w ⇒ A= C_(Earth) w We find the circumference of the Earth using the formula for the circumference of a circle. C=2π r Let's calculate this circumference using that the Earth has a radius of about 3960 miles.
C=2π r
C=2π ( 3960)
Simplify right-hand side
C=2(3960)π
C= 7920π
In the exercise we are told that the width of the Torrid Zone is 3250 miles. We can now calculate its surface area. A= C_(Earth) w ⇓ A= 7920π( 3250)≈ 80.9 million mi^2
b
To find the probability that a meteorite hits in the Torrid Zone we will divide the area of the Torrid Zone with the area of the Earth. P=A_(Torrid Zone)/A_(Earth)In Part A we used that the surface area of the Torrid Zone is the product of the circumference of the Earth, 2π r, and the width of the Torrid Zone, w. A_(Torrid Zone)= 2π r* w To find the surface area of the Earth we will use the formula for the surface area of a sphere. A_(Earth)= 4π r^2 Let's calculate the probability that a meteorite will land in the Torrid Zone.
P=A_(Torrid Zone)/A_(Earth)
P=2π r* w/4π r^2
P=w/2 r
P=3250/2 ( 3960)
Evaluate right-hand side
P=0.41035...
P≈ 0.41
The probability is about 0.41, or 41 %.