Big Ideas Math Geometry, 2014
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Big Ideas Math Geometry, 2014 View details
8. Surface Areas and Volumes of Spheres
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Exercise 23 Page 653

Subtract the volume of the hemisphere from the volume of the cylinder.

425/3 π ≈ 445.06 in.^3

Practice makes perfect

We want to find the volume of a composite solid in the shape of a cylinder with a hemisphere hollowed out of it.

Cylinder with a hemisphere hollowed out of it

We will first find the volume of the cylinder and then the volume of the hemisphere. Then we can subtract the latter from the former to find the volume of the composite solid. Let's do it!

Volume of the Cylinder

Let's begin by finding the volume of the cylinder.

A 9 inches high cylinder with a radius of 5 inches
The volume of a cylinder is the product of the area of the base and the height. V=Bh Our cylinder has a circular base, B, and its area is the product of π times the radius squared. V=Bh ⇒ V = π r^2 h Let's substitute the corresponding values into the formula and find its volume.
V = π r^2 h
V = π ( 5)^2 ( 9)
Simplify right-hand side
V = π (25) (9)
V = π (225)
V = 225π
The cylinder has a volume of 225 πin.^3.

Volume of the Hemisphere

The shape of a hemisphere is hollowed out of the cylinder.

Cylinder with a hemisphere hollowed out of it. The hemispherical hollow is highlighted
The volume of a hemisphere is half the volume of a sphere. V=43π r^3/2 ⇔ V = 2/3π r^3 Our hemisphere-shaped hollow has a radius of 5 inches. Let's find its volume.
V = 2/3π r^3
V = 2/3π ( 5)^3
Simplify right-hand side
V = 2/3π (125)
V = 2/3(125)π
V = 2(125)/3π
V = 250/3π

Volume of the Solid

To find the volume of the composite solid, we will subtract the volume of the hemisphere from the volume of the cylinder. V_(solid)= V_(cylinder)- V_(hemisphere) ⇓ V_(solid)= 225π- 250/3π = 425/3 π The composite solid has the volume 4253 π ≈ 445.06 in.^3.