Use the formula for volume of a sphere to find the volume of the hemisphere.
7/3 π ≈ 7.3 m^3
Practice makes perfect
We want to find the volume of a composite solid in the shape of a cone with a hemisphere attached to it.
We will first find the volume of the cone and then the volume of the hemisphere. We can then add the results to find the volume of the solid. Let's do it!
Volume of the Cone
Let's begin by finding the volume of the cone.
The volume of a cone is one third the product of the area of the base and the height.
V=1/3 Bh
Our cone has a circular base, B, and its area is the product of π times the radius squared.
V=1/3 Bh ⇒ V = 1/3 π r^2 h
Let's substitute the corresponding values into the formula and find its volume.
The top section of the solid is in the shape of a hemisphere.
The volume of a hemisphere is half the volume of a sphere.
V=43π r^3/2 ⇒ V = 2/3π r^3
We can now find the volume our hemisphere, which has a radius of 1 meter.
V = 2/3π ( 1)^3 ⇔ V= 2/3π
The hemisphere has a volume of 23πm^3.
Volume of the Solid
To find the volume of the composite solid we will use the Volume Addition Postulate.
The volume of a solid is the sum of the volumes of all its non-overlapping parts.
The solid has two non-overlapping parts, one cone and one hemisphere. Let's add their volumes.
V_(solid)= V_(cone)+ V_(hemisphere)
⇓
V_(solid)= 5/3π+ 2/3π = 7/3 π
The solid has the volume 73 π ≈ 7.3 m^3.
