Big Ideas Math Geometry, 2014
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Big Ideas Math Geometry, 2014 View details
1. Circumference and Arc Length
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Exercise 30 Page 599

Notice that ∠ 1 and ∠ 2 are congruent by the Alternate Interior Angles Theorem.

See solution.

Practice makes perfect

Let's take a look at the diagram. We are given that l_1 and l_2 are parallel, and the measure of ∠ 2 is 7.2^(∘).

First, notice that ∠ 1 and ∠ 2 are alternate interior angles. Therefore, by the Alternate Interior Angles Theorem these angles are congruent and both have measures of 7.2^(∘).

Next we are given that the distance between Syene and Alexandria is approximately 575 miles. Let's add this information to our diagram.

If we call the radius of Earth r, then we can write that the distance from the center of the Earth to each of the towns is equal to r.

Notice that we can find the radius of the Earth using the Law of Cosines. We will write the equation according to this law. 575^2= r^2+ r^2-2( r)( r)cos 7.2^(∘) Let's solve the above equation to find r. Remember that since r needs to be a positive number we will consider only the principal root of r^2.
575^2=r^2+r^2-2(r)(r)cos 7.2^(∘)
Solve for r^2
330 625=r^2+r^2-2(r)(r)cos 7.2^(∘)
330 625=r^2+r^2-2cos 7.2^(∘) r^2
330 625=r^2(1+1-2cos7.2^(∘))
330 625/1+1-2cos7.2^(∘)=r^2
r^2=330 625/1+1-2cos7.2^(∘)
r^2=330 625/2-2cos7.2^(∘)
r=sqrt(330 625/2-2cos7.2^(∘))
r=4578.7166...
r≈ 4579
The radius of Earth is approximately 4579 miles. Finally we can evaluate the circumference of Earth. Let's recall that the circumference of a circle is two times the product of a radius and pi. C=2π( 4579)≈ 28 771 Using Eratosthenes' Method we found that the circumference of Earth is approximately 28 771 miles.