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To complete the square make sure all the variable terms are on one side of the equation. Then, divide both sides of the equation by a so the coefficient of x^2 is 1.
x_1=1, x_2=- 7
We want to solve the quadratic equation by completing the square.To do so, we will start by rewriting the equation so all terms with x are on one side of the equation.
2x^2+12x+20=34 ⇔ 2x^2+12x=14
Now let's divide each side by 2 so the coefficient of x^2 will be 1.
Next, we will add ( b2 )^2=9 to both sides of our equation. Then we will factor the trinomial on the left-hand side and solve the equation.
LHS+9=RHS+9
a^2+2ab+b^2=(a+b)^2
Add terms
sqrt(LHS)=sqrt(RHS)
Calculate root
LHS-3=RHS-3
We conclude that the equation has two solutions. x_1&=- 3+4=1 x_2&=- 3-4=- 7