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The center of the circle will be the point of intersection of the perpendicular bisectors of the sides of â–ł XYZ.
Equation: (x-4)^2+(y-9)^2=16
Explanation: See solution.
We are given the vertices of â–ł XYZ and asked to evaluate the equation of the circle circumscribed about this triangle. First, let's draw this triangle in the coordinate plane.
Substitute ( 4,13) & ( 8,9)
Subtract terms
Put minus sign in front of fraction
Calculate quotient
Finally, we can write the equation of this circle by substituting the center point and the radius into the standard equation of a circle. (x-4)^2+(y-9)^2= 4^2 ⇓ (x-4)^2+(y-9)^2=16