Big Ideas Math Algebra 1, 2015
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Big Ideas Math Algebra 1, 2015 View details
6. Transformations of Graphs of Linear Functions
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Exercise 72 Page 154

Rewrite this inequality as a compound inequality.

Solution Set: -12 < x < -2
Graph:

Practice makes perfect
We are asked to find and graph the solution set for all possible values of x in the given inequality. 5|x+7| < 25 To do this let's start by simplifying it.
5|x+7|<25
|x+7|<5

Now, we will create a compound inequality by removing the absolute value. In this case, the solution set is any number less than 5 away from the midpoint in the positive direction and any number less than 5 away from the midpoint in the negative direction. Absolute Value Inequality:& |x+7| < 5 Compound Inequality:& - 5< x+7 < 5 Since we can write x+7 as x-(-7), the solution set of this compound inequality contains the numbers that make the distance between x and - 7 greater than - 5 and less than 5. x+7>-5 and x+7 < 5 Let's isolate x in both of these cases before graphing the solution set.

Case 1

x+7 >-5
x > -12
This inequality tells us that all values greater than -12 will satisfy the inequality.

Case 2

x+7<5
x<-2
This inequality tells us that all values less than -2 will satisfy the inequality.

Solution Set

The solution to this type of compound inequality is the overlap of the solution sets. Let's recombine our cases back into one compound inequality. First Solution Set:& -12 < x Second Solution Set:& x < -2 Intersecting Solution Set:& -12 < x < -2

Graph

The graph of this inequality includes all values from -12 to -2, not inclusive. We will show this by using open circles on the endpoints.