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{{ printedBook.courseTrack.name }} {{ printedBook.name }} Let's plot the given points on the same coordinate plane as the system of inequalities.

When looking at the four points, the first thing we can notice is that $(0,-4)$ and $(-1,-6)$ lie squarely within the solution set, and the points $(1,-2)$ and $(2,-4)$ rest on the boundary lines. What does it mean when a line is dashed and when it is solid?

**A solid line**tells us that the inequality is**not**strict. Therefore, the points on the boundary line are solutions to the inequality.**A dashed line**tells us that the inequality**is strict.**Therefore, the points on the boundary line are**not**solutions to the inequality.

With the above in mind, we can conclude that $(2,-4)$ is a solution to the system because it lies on a solid line. However, the point $(1,-2),$ which lies on both a solid and a dashed line, is a solution to one of the inequalities but **not** a solution to the other. Therefore, $(1,-2)$ does not belong with the others as it is not a solution.