Solving One-Step Equations

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Algebra 1

One-Variable Equations

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Solving One-Step Equations 1.4 - Solution

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a

Solve the equation by adding $10$ to both sides. This way, we'll get $x$ isolated on the left-hand side.

$x - 10 = 27$

AddEqn$\text{LHS}+10=\text{RHS}+10$

$x = 37$

The solution to the equation is $x=37.$

b

On the left-hand side of the equation we have $5y.$ Therefore, to isolate $y$ we need to divide both sides by $5.$

$5y = 20$

DivEqn$\left.\text{LHS}\middle/5\right.=\left.\text{RHS}\middle/5\right.$

$y = 4$

c

On the left-hand side of the equation, we have $\frac{z}{3}.$ If we multiply both sides by $3,$ we can isolate $z.$

$\dfrac{z}{3} = 7$

MultEqn$\text{LHS} \cdot 3=\text{RHS}\cdot 3$

$\dfrac{z}{3} \cdot 3 = 7 \cdot 3$

FracMultDenomToNumber$\dfrac{a}{3}\cdot 3 = a$

$z = 7 \cdot 3$

MultiplyMultiply

$z = 21$