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Solving One-Step Equations
Choose Course
Algebra 1
One-Variable Equations
Solving One-Step Equations
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Solving One-Step Equations 1.4 - Solution
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Return to Solving One-Step Equations
a
Solve the equation by adding
10
10
1
0
to both sides. This way, we'll get
x
x
x
isolated on the left-hand side.
x
−
10
=
27
x - 10 = 27
x
−
1
0
=
2
7
AddEqn
LHS
+
10
=
RHS
+
10
\text{LHS}+10=\text{RHS}+10
LHS
+
1
0
=
RHS
+
1
0
x
=
37
x = 37
x
=
3
7
The solution to the equation is
x
=
37.
x=37.
x
=
3
7
.
b
On the left-hand side of the equation we have
5
y
.
5y.
5
y
.
Therefore, to isolate
y
y
y
we need to divide both sides by
5.
5.
5
.
5
y
=
20
5y = 20
5
y
=
2
0
DivEqn
LHS
/
5
=
RHS
/
5
\left.\text{LHS}\middle/5\right.=\left.\text{RHS}\middle/5\right.
LHS
/
5
=
RHS
/
5
y
=
4
y = 4
y
=
4
c
On the left-hand side of the equation, we have
z
3
.
\frac{z}{3}.
3
z
.
If we multiply both sides by
3
,
3,
3
,
we can isolate
z
.
z.
z
.
z
3
=
7
\dfrac{z}{3} = 7
3
z
=
7
MultEqn
LHS
⋅
3
=
RHS
⋅
3
\text{LHS} \cdot 3=\text{RHS}\cdot 3
LHS
⋅
3
=
RHS
⋅
3
z
3
⋅
3
=
7
⋅
3
\dfrac{z}{3} \cdot 3 = 7 \cdot 3
3
z
⋅
3
=
7
⋅
3
FracMultDenomToNumber
a
3
⋅
3
=
a
\dfrac{a}{3}\cdot 3 = a
3
a
⋅
3
=
a
z
=
7
⋅
3
z = 7 \cdot 3
z
=
7
⋅
3
Multiply
Multiply
z
=
21
z = 21
z
=
2
1