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Solving One-Step Equations
Choose Course
Algebra 1
One-Variable Equations
Solving One-Step Equations
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Solving One-Step Equations 1.2 - Solution
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Return to Solving One-Step Equations
We substitute
3
3
3
for
x
x
x
in the equation. If the left- and right-hand sides are equal, then
x
=
3
x=3
x
=
3
is a solution.
17
+
5
x
=
47
−
4
x
−
3
17 + 5x = 47 - 4x - 3
1
7
+
5
x
=
4
7
−
4
x
−
3
Substitute
x
=
3
x={\color{#0000FF}{3}}
x
=
3
17
+
5
⋅
3
=
?
47
−
4
⋅
3
−
3
17 + 5 \cdot {\color{#0000FF}{3}} \stackrel{?}{=} 47 - 4 \cdot {\color{#0000FF}{3}} - 3
1
7
+
5
⋅
3
=
?
4
7
−
4
⋅
3
−
3
Multiply
Multiply
17
+
15
=
?
47
−
12
−
3
17 + 15 \stackrel{?}{=} 47 - 12 - 3
1
7
+
1
5
=
?
4
7
−
1
2
−
3
AddSubTerms
Add and subtract terms
32
=
32
32 =32
3
2
=
3
2
Both sides of the equation are equal to
32.
32.
3
2
.
Thus,
x
=
3
x=3
x
=
3
solves the equation.
