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| Student Learning Objectives: |
|---|
|
| | 9 Theory slides |
| | 10 Exercises - Grade E - A |
| | Each lesson is meant to take 1-2 classroom sessions |
The applet shows some terms in a table. Try to group the terms in the table correctly.
Two or more terms in an algebraic expression are like terms if they have the same variable(s) with the same exponent(s). 7xy+2x-3xy-2x^2+x+5x^2 In this expression, there are three sets of like terms — namely, xy-terms, x-terms, and x^2-terms.
Determine whether the terms are like terms.
Once like terms are identified, it is possible to combine them using addition or subtraction.
In an expression, groups of like terms can be combined to write an equivalent expression with the least possible number of terms. As an example, consider the following expression. 7xy+2x-3xy-2x^2+x+5x^2 There are three steps to follow to combine like terms.
Now that all like terms have been combined, the initial expression has been reduced to its simplest form. 7xy+2x-3xy-2x^2+x+5x^2 ⇕ 4xy+3x+3x^2
Heichi got a part-time summer job at a local history museum. He asked his sister for directions from home to the museum. She drew a map for him. She also knows that Heichi is studying algebraic expressions, so she used algebraic expressions to show the relevant distances.
Write an expression in its simplest form for the total distance from Heichi's house to the museum.
| Section | Expression |
|---|---|
| First Leg | x |
| Second Leg | 3x+7 |
| Third Leg | 4x-6 |
These expressions can be added together to find the total distance. x+ 3x+7+ 4x-6 Notice that there are two different terms — x-terms and constant terms. These are the like terms. x+ 3x+ 7+ 4x - 6 Now that the like terms have been identified, they can be combined. Use the Commutative Property of Addition to group the like terms together, then add or subtract them.
Commutative Property of Addition
Add terms
Subtract term
The simplified expression is 8x+1.
On weekends, the museum has special admission prices before noon.
Children pay x dollars and adults pay x^2 dollars before noon. After noon, the prices go up to y and y^2 dollars for children and adults, respectively. Heichi kept track of the number of visitors on both Saturday and Sunday in separate tables. The following table shows the number of visitors on Saturday.
| Saturday's Visitors | ||
|---|---|---|
| Children | Adults | |
| Before Noon | 7 | 12 |
| After Noon | 12 | 20 |
The table below shows the number of visitors on Sunday.
| Sunday's Visitors | ||
|---|---|---|
| Children | Adults | |
| Before Noon | 8 | 15 |
| After Noon | 3 | 4 |
Help Heichi figure out how much money the museum took in from admissions on Saturday and Sunday in terms of x and y. Then simplify the total amount.
| Saturday's Visitors | |||
|---|---|---|---|
| Children ($) | Adults ($) | Total ($) | |
| Before Noon | 7x | 12x^2 | 7x+ 12x^2 |
| After Noon | 12y | 20y^2 | 12y+ 20y^2 |
The expression for Saturday's revenue can be written by adding the expressions for each part of the day. Saturday's Revenue ($) 7x + 12x^2 + 12y + 20y^2 The same steps can be followed for Sunday's visitors.
| Sunday's Visitors | |||
|---|---|---|---|
| Children ($) | Adults ($) | Total ($) | |
| Before Noon | 8x | 15x^2 | 8x+ 15x^2 |
| After Noon | 3y | 4y^2 | 3y+ 4y^2 |
Similar to Saturday, the expression for Sunday's revenue can be found by adding the expressions for each part of the day. Sunday's Revenue ($) 8x + 15x^2 + 3y + 4y^2 Now that the expressions for Saturday and Sunday are written, it is time to add them together. The like terms can be grouped by the Commutative Property of Addition to combine them easily.
Commutative Property of Addition
Add terms
This expression represents how much money was made from admissions over the weekend.
Heichi's friend Magdalena works at the souvenir shop in the museum. There are three large items that are sold in the shop.
Magdalena told Heichi that three groups of people visited the shop on Saturday.
The curious thing, Magdalena explained, is that the exact same thing happened on Sunday. Suppose that the items returned are fully refunded. Write and simplify an expression for how much money the shop made from these groups of people over the weekend.
The money exchanged for each set of items is the product of the number of items sold and its corresponding price. Note that when an item is returned, the prices are negative because money is being taken from the shop and returned to the customer.
| Vases ($) | Plush Toys ($) | Paintings ($) | Total ($) | |
|---|---|---|---|---|
| First Group | 3a | 4b | 5c | 3a+ 4b+ 5c |
| Second Group | - 2a | 6b | 1c | - 2a+ 6b+ 1c |
| Third Group | 1a | 0 | - 1c | 1a- 1c |
The expression for the money made on Saturday is the sum of these expressions. Saturday's Revenue ($) 3a + 4b + 5c+ 6b - 2a + 1c - 1c + 1a Magdalena mentioned that the same thing happened on Sunday. This means that the whole expression has to be multiplied by 2 to find the expression for the money made from both days. Weekend Revenue ($) 2( 3a + 4b + 5c+ 6b - 2a + 1c - 1c + 1a) This expression can be simplified by combining like terms first and then distributing the 2 or by distributing first. Either process will result in the simplified expression. Here, the terms will be combined first.
Commutative Property of Addition
Add terms
Subtract terms
Distribute 2
Multiply
This expression represents the total revenue from these groups on both Saturday and Sunday.
The beginning of this lesson presented a table to group like terms.
Consider the following expression. 8y + 4 + 9y +4y +9 - 6 Adding one set of parentheses makes this expression equivalent to the expression 7(3y+5). Rewrite the expression with these parentheses without rearranging the terms.
Consider the given expression. 8y + 4 + 9y +4y +9 - 6 We want to add one set of parentheses to the given expression so that it is equivalent to 7(3y+5). Let's start by simplifying the expression with parentheses to make it easier to compare. We can use the Distributive Property.
Now let's consider the given expression again. We can discard some possible placements of the parentheses without performing any of the operations. We know that we will not need to add the parentheses in a place where the order of operations makes them irrelevant. For example, we do not need to add parentheses to multiply before adding. (8y ) + 4 + (9y ) + (4y ) +9 - 6 We also want to avoid adding parentheses that would result in multiplying two y-terms together. (8y + 4 + 9 )y +4y +9 - 6 If we distributed y in the expression, we would have a y^2-term. Our equivalent expression does not have any y^2-terms, so we know not to place the parentheses here. Consider the following three options.
Let's simplify the expressions.
| Expression | Distribute | Simplify |
|---|---|---|
| 8(y + 4) + 9y +4y +9 - 6 | 8y + 32 + 9y +4y +9 - 6 | 21y+35 |
| 8y + 4 + 9y +4(y +9) - 6 | 8y + 4 + 9y +4y +36 - 6 | 21y+34 |
| 8y + 4 + 9y +4(y +9 - 6) | 8y + 4 + 9y +4y +36 - 24 | 21y+56 |
We can see that the first expression is equivalent to 7(3y+5). Good job!
Find the difference between the perimeters of the rectangle and the pentagon.
We want to find the difference between the perimeters of the given figures.
First, we need to find the perimeter of each figure. Remember that the perimeter measures the distance around the outside of a two-dimensional figure. To determine the perimeter of a figure, add up all of its side lengths. Let's start by adding the given lengths of the rectangle together. a + 2a+3 = 3a+3 In a rectangle, each pair of sides has the same length. Because of this, we can multiply our expression by 2 to find the whole perimeter. Let's use the Distributive Property.
We have an expression for the perimeter of the rectangle. We are making great progress! Now let's add the given side lengths of the pentagon.
Finally, let's calculate the difference between the perimeters.
Since the difference is 0, the perimeters of the rectangle and the pentagon are equal!