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| 9 Theory slides |
| 10 Exercises - Grade E - A |
| Each lesson is meant to take 1-2 classroom sessions |
Here are a few recommended readings before getting started with this lesson.
Determine whether the terms are like terms.
Once like terms are identified, it is possible to combine them using addition or subtraction.
Heichi got a part-time summer job at a local history museum. He asked his sister for directions from home to the museum. She drew a map for him. She also knows that Heichi is studying algebraic expressions, so she used algebraic expressions to show the relevant distances.
Heichi is trying to determine the overall distance from his house to the museum along the route his sister marked for him. The route is broken into three separate sections. Each section has a unique length represented by a unique algebraic expression.
Section | Expression |
---|---|
First Leg | x |
Second Leg | 3x+7 |
Third Leg | 4x−6 |
Commutative Property of Addition
Add terms
Subtract term
On weekends, the museum has special admission prices before noon.
Children pay x dollars and adults pay x2 dollars before noon. After noon, the prices go up to y and y2 dollars for children and adults, respectively. Heichi kept track of the number of visitors on both Saturday and Sunday in separate tables. The following table shows the number of visitors on Saturday.
Saturday's Visitors | ||
---|---|---|
Children | Adults | |
Before Noon | 7 | 12 |
After Noon | 12 | 20 |
The table below shows the number of visitors on Sunday.
Sunday's Visitors | ||
---|---|---|
Children | Adults | |
Before Noon | 8 | 15 |
After Noon | 3 | 4 |
Remember that the tickets have different prices depending on the time of day.
Saturday's Visitors | |||
---|---|---|---|
Children ($) | Adults ($) | Total ($) | |
Before Noon | 7x | 12x2 | 7x+12x2 |
After Noon | 12y | 20y2 | 12y+20y2 |
Sunday's Visitors | |||
---|---|---|---|
Children ($) | Adults ($) | Total ($) | |
Before Noon | 8x | 15x2 | 8x+15x2 |
After Noon | 3y | 4y2 | 3y+4y2 |
Commutative Property of Addition
Add terms
Heichi's friend Magdalena works at the souvenir shop in the museum. There are three large items that are sold in the shop.
Magdalena told Heichi that three groups of people visited the shop on Saturday.
Start by writing an expression for Saturday. Then, multiply that expression by 2.
Start by writing an expression to find the amount of money made by the store on Saturday. Consider each group separately.
The money exchanged for each set of items is the product of the number of items sold and its corresponding price. Note that when an item is returned, the prices are negative because money is being taken from the shop and returned to the customer.
Vases ($) | Plush Toys ($) | Paintings ($) | Total ($) | |
---|---|---|---|---|
First Group | 3a | 4b | 5c | 3a+4b+5c |
Second Group | -2a | 6b | 1c | -2a+6b+1c |
Third Group | 1a | 0 | -1c | 1a−1c |
Commutative Property of Addition
Add terms
Subtract terms
Distribute 2
Multiply
Consider the given expression. 8y + 4 + 9y +4y +9 - 6 We want to add one set of parentheses to the given expression so that it is equivalent to 7(3y+5). Let's start by simplifying the expression with parentheses to make it easier to compare. We can use the Distributive Property.
Now let's consider the given expression again. We can discard some possible placements of the parentheses without performing any of the operations. We know that we will not need to add the parentheses in a place where the order of operations makes them irrelevant. For example, we do not need to add parentheses to multiply before adding. (8y ) + 4 + (9y ) + (4y ) +9 - 6 We also want to avoid adding parentheses that would result in multiplying two y-terms together. (8y + 4 + 9 )y +4y +9 - 6 If we distributed y in the expression, we would have a y^2-term. Our equivalent expression does not have any y^2-terms, so we know not to place the parentheses here. Consider the following three options.
Let's simplify the expressions.
Expression | Distribute | Simplify |
---|---|---|
8(y + 4) + 9y +4y +9 - 6 | 8y + 32 + 9y +4y +9 - 6 | 21y+35 |
8y + 4 + 9y +4(y +9) - 6 | 8y + 4 + 9y +4y +36 - 6 | 21y+34 |
8y + 4 + 9y +4(y +9 - 6) | 8y + 4 + 9y +4y +36 - 24 | 21y+56 |
We can see that the first expression is equivalent to 7(3y+5). Good job!
Find the difference between the perimeters of the rectangle and the pentagon.
We want to find the difference between the perimeters of the given figures.
First, we need to find the perimeter of each figure. Remember that the perimeter measures the distance around the outside of a two-dimensional figure. To determine the perimeter of a figure, add up all of its side lengths. Let's start by adding the given lengths of the rectangle together. a + 2a+3 = 3a+3 In a rectangle, each pair of sides has the same length. Because of this, we can multiply our expression by 2 to find the whole perimeter. Let's use the Distributive Property.
We have an expression for the perimeter of the rectangle. We are making great progress! Now let's add the given side lengths of the pentagon.
Finally, let's calculate the difference between the perimeters.
Since the difference is 0, the perimeters of the rectangle and the pentagon are equal!