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This lesson focuses on simplifying algebraic expressions, a fundamental skill in algebra. It teaches how to identify like terms in an expression and combine them to make the expression simpler. This skill is particularly useful in various real-world scenarios, such as calculating total costs or distances. For example, if someone is trying to figure out the total distance for a multi-leg journey, they can use these techniques to combine the distances into a single, simpler expression. Understanding how to simplify algebraic expressions can make problem-solving quicker and more efficient, whether you're a student or a professional dealing with data analysis.
Show less Show more expand_more| Student Learning Objectives: |
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| | 9 Theory slides |
| | 10 Exercises - Grade E - A |
| | Each lesson is meant to take 1-2 classroom sessions |
Group the terms in the table correctly.
Two or more terms in an algebraic expression are like terms if they have the same variable(s) with the same exponent(s). 7xy+2x-3xy-2x^2+x+5x^2 In this expression, there are three sets of like terms — xy-terms, x-terms, and x^2-terms.
Are the terms are like terms?
Once we identify like terms in an expression, we can combine them using addition or subtraction.
In an expression, groups of like terms can be combined to write an equivalent expression with the least possible number of terms. Consider the following expression. 7xy+2x-3xy-2x^2+x+5x^2 There are three steps to follow to combine like terms.
Now that all like terms have been combined, the initial expression has been reduced to its simplest form. 7xy+2x-3xy-2x^2+x+5x^2 ⇕ 4xy+3x+3x^2
The map shows a path from Heichi's house to the museum. The distances are given as algebraic expressions.
Write an expression in simplest form for the total distance from Heichi's house to the museum.
Identify the like terms and then combine them.
Commutative Property of Addition
Add terms
Subtract term
The simplified expression is 8x+1.
On weekends, the museum has special admission prices before noon.
Children pay x dollars and adults pay x^2 dollars before noon. After noon, the prices go up to y and y^2 dollars for children and adults, respectively. Heichi kept track of the number of visitors on both Saturday and Sunday in separate tables. The following table shows the number of visitors on Saturday.
| Saturday Visitors | Sunday Visitors | |||
|---|---|---|---|---|
| Children | Adults | Children | Adults | |
| Before Noon | 7 | 12 | 8 | 15 |
| After Noon | 12 | 20 | 3 | 4 |
How much money did the museum take in from admissions on Saturday and Sunday in terms of x and y? Simplify the total amount.
| Saturday Visitors | |||
|---|---|---|---|
| Children ($) | Adults ($) | Total ($) | |
| Before Noon | 7x | 12x^2 | 7x+ 12x^2 |
| After Noon | 12y | 20y^2 | 12y+ 20y^2 |
Now, we can write the expression for Saturday's revenue by adding the expressions for each part of the day. Saturday's Revenue ($) 7x + 12x^2 + 12y + 20y^2 Let's follow the same steps for Sunday.
| Sunday Visitors | |||
|---|---|---|---|
| Children ($) | Adults ($) | Total ($) | |
| Before Noon | 8x | 15x^2 | 8x+ 15x^2 |
| After Noon | 3y | 4y^2 | 3y+ 4y^2 |
Next, we can write the expression for Sunday's revenue by adding the expressions for each part of the day. Sunday's Revenue ($) 8x+ 15x^2+ 3y+ 4y^2 Finally, we can find the total revenue for the weekend by adding the revenues for both days. Let's use the Commutative Property of Addition to group the like terms so we can combine them.
Commutative Property of Addition
Add terms
The total revenue for the weekend is 15x+15y+27x^2+24y^2 dollars.
The souvenir shop at a museum sells three large items.
Three groups of people visited the shop on Saturday.
The exact same thing happened on Sunday. Suppose that the items returned are fully refunded. Write and simplify an expression for how much money the shop made from these groups of people over the weekend.
| Vases ($) | Plush Toys ($) | Paintings ($) | Total ($) | |
|---|---|---|---|---|
| First Group | 3a | 4b | 5c | 3a+ 4b+ 5c |
| Second Group | -2a | 6b | 1c | -2a+ 6b+ 1c |
| Third Group | 1a | 0 | -1c | 1a - 1c |
The sum of these expressions gives us the money the store made on Saturday. Saturday's Revenue ($) 3a + 4b + 5c+ 6b - 2a + 1c - 1c + 1a The same thing happened on Sunday. To find the money the store made on both days, we multiply the whole expression by 2. Weekend Revenue ($) 2( 3a + 4b + 5c+ 6b - 2a + 1c - 1c + 1a) We can simplify the expression by combining like terms and then distributing the 2. Let's combine the terms first.
Commutative Property of Addition
Add terms
Subtract terms
Distribute 2
Multiply
The total revenue for the weekend is 4a+20b+10c dollars.
The beginning of this lesson presented a table to group like terms.
Consider the following expression. 8y + 4 + 9y +4y +9 - 6 Adding one set of parentheses makes this expression equivalent to the expression 7(3y+5). Rewrite the expression with these parentheses without rearranging the terms.
Consider the given expression. 8y + 4 + 9y +4y +9 - 6 We want to add one set of parentheses to the given expression so that it is equivalent to 7(3y+5). Let's start by simplifying the expression with parentheses to make it easier to compare. We can use the Distributive Property.
Now let's consider the given expression again. We can discard some possible placements of the parentheses without performing any of the operations. We know that we will not need to add the parentheses in a place where the order of operations makes them irrelevant. For example, we do not need to add parentheses to multiply before adding. (8y ) + 4 + (9y ) + (4y ) +9 - 6 We also want to avoid adding parentheses that would result in multiplying two y-terms together. (8y + 4 + 9 )y +4y +9 - 6 If we distributed y in the expression, we would have a y^2-term. Our equivalent expression does not have any y^2-terms, so we know not to place the parentheses here. Consider the following three options.
Let's simplify the expressions.
| Expression | Distribute | Simplify |
|---|---|---|
| 8(y + 4) + 9y +4y +9 - 6 | 8y + 32 + 9y +4y +9 - 6 | 21y+35 |
| 8y + 4 + 9y +4(y +9) - 6 | 8y + 4 + 9y +4y +36 - 6 | 21y+34 |
| 8y + 4 + 9y +4(y +9 - 6) | 8y + 4 + 9y +4y +36 - 24 | 21y+56 |
We can see that the first expression is equivalent to 7(3y+5). Good job!
Find the difference between the perimeters of the rectangle and the pentagon.
We want to find the difference between the perimeters of the given figures.
First, we need to find the perimeter of each figure. Remember that the perimeter measures the distance around the outside of a two-dimensional figure. To determine the perimeter of a figure, add up all of its side lengths. Let's start by adding the given lengths of the rectangle together. a + 2a+3 = 3a+3 In a rectangle, each pair of sides has the same length. Because of this, we can multiply our expression by 2 to find the whole perimeter. Let's use the Distributive Property.
We have an expression for the perimeter of the rectangle. We are making great progress! Now let's add the given side lengths of the pentagon.
Finally, let's calculate the difference between the perimeters.
Since the difference is 0, the perimeters of the rectangle and the pentagon are equal!