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| 8 Theory slides |
| 8 Exercises - Grade E - A |
| Each lesson is meant to take 1-2 classroom sessions |
Here are a few recommended readings before getting started with this lesson.
Jordan is the head of security at a famous casino hotel named The Compazu in Las Vegas. She decided to have a safe room constructed after a heist took place. About its design, the safe room will be circular, and three security cameras will monitor it. One of the cameras will be opposite the entrance door.
An equilateral triangle can be constructed in several ways. One method is to use two intersecting circles.
An equilateral triangle is a triangle with three congruent sides.
It can be constructed using a compass and a straightedge.
Begin by drawing a circle centered at point A. Then identify an arbitrary point B on the circumference.
Place the compass at point B and draw another circle passing through point A. Then identify one of the intersection points of the circles as point C.
Connect the points using a straightedge.
Note that point A and point B are the centers of ⊙A and ⊙B, respectively. Since ⊙A passes through point B and ⊙B passes through point A, the radii of the circles are equal. Therefore, AB, BC, and AC are equal. Consequently, △ABC is an equilateral triangle.
Given a square and a circle, use the applet to place the circle such that the square is inscribed in the circle. Then draw the diagonals of the square.
Considering the previous exploration, when given a circle, the construction of a square can be done using a compass and a straightedge.
A square that is inscribed in a circle can be constructed in a few of steps.
Given a circle, these three steps can be followed to construct a square inscribed in the circle.
Begin by drawing an arbitrary diameter of ⊙O using a straightedge. Identify the endpoints as A and C.
Next, draw a segment perpendicular to AC at point O. This will be another diameter of ⊙O. Identify its endpoints as B and D.
Finally, by connecting the endpoints of the diameters, an inscribed square can be drawn.
Note that diagonals of a square are congruent and they are the perpendicular bisectors of each other. Since AC and BD are congruent and they are perpendicular bisectors of each other, polygon ABCD is a square.
A regular pentagon can be inscribed in a circle using a compass and straightedge.
The following steps can be followed to construct a regular pentagon.
Given a circle, begin by drawing an arbitrary diameter. Then identify the endpoints of the diameter as C and M.
Construct a perpendicular segment to CM at point O. After that identify the point of intersection of the circle and the perpendicular segment as S.
Next, draw a circle centered at point L with a radius of SL. Then draw a line passing through point M and point L intersecting ⊙L. From here, identify the intersection points of ⊙L and the segment as N and P.
Now, two arcs centered at point M will be drawn. Both arcs will intersect ⊙O. One of them will pass through point P and the other one will pass through point N. Label the intersection points of the arcs and ⊙O as A, E, B, and D.
Finally, connect points A, B, C, D, and E.
None of the previous constructions will help Jordan. Finally, by using a compass and a straightedge, a regular hexagon will be constructed hoping that it will help Jordan. Otherwise, she may lose her job.
These three steps can be followed to construct a regular hexagon inscribed in a circle.
Given ⊙O, place the compass on an arbitrary point on the circumference of the circle. Then draw a circle passing through the center of ⊙O and identify one of the intersection points as B.
Next, place the compass at point B and draw another circle passing through the center of ⊙O. Repeat the process until ⊙O is intercepted six times and label the intersection points as C, D, E, and F.
Finally, connect the points using a straightedge.
Therefore, a regular hexagon ABCDEF has been constructed.
Notice that a regular hexagon consists of six equilateral triangles that are congruent.
By repeating the process of constructing an equilateral triangle several times, the vertices of the polygon has been found. Therefore, the resulting polygon is a regular hexagon.
Among all of the constructions covered in this lesson, there is one in particular that will help Jordan place the cameras correctly — slowing any attempted heist! Recall that Jordan wants to determine the positions of the three cameras, given that one of the cameras will be opposite the entrance door.
She came ready with a compass, a straightedge, and the blueprint of the room. Show how she can determine the positions of the other two cameras.
See solution.
Follow the process of inscribing a regular hexagon in a circle.
Following the process of inscribing a regular hexagon in a circle, first determine six points on the circle. The starting point will be the position of the first security camera.
According to the construction, each point on the circle is equidistant from each other. Therefore, it can be concluded that the distances between every other point are also equal.
Therefore, Jordan can determine the position of the cameras by choosing every other point starting from the position of the first point — Camera 1.
With this camera setup, Jordan can have three security cameras equidistant from each other, adequately monitoring The Compazu's safe room.
Let's will construct an equilateral triangle considering the given steps by ourselves. We need a circle to start our construction. We should first mark the center of the circle. Since point B is somewhere on ⊙ A, our first step will be marking point A on our paper.
Now we can construct a circle with center at A using a compass.
We need another circle. Let's mark point B somewhere on ⊙ A.
We need to determine the radius of the circle to construct it. To do so, we will set compass width to AB.
Now that the we determined the radius of the circle, we can construct it centered at point B.
We are almost there! We have two points but we need three points to construct a triangle. We will mark point C on either of the intersection points of ⊙ A and ⊙ B.
Finally, we will connect these points with a straightedge.
We can order the steps as follows based on our construction.
Emily creates an equilateral triangle using a compass and straightedge.
We have been given a construction of an equilateral triangle. We want to construct a hexagon by completing this construction. Note that we will need six vertices. We should first set the compass width to AO based on the given steps.
Now we will put the compass point on B and draw another circle.
Next, we will mark the new intersection point C and repeat the process until we have six vertices.
In our last step, we will connect these points using a straightedge.
Based on our construction, the steps can be followed in the following order.
Zosia wants to construct an isosceles trapezoid inscribed in a circle using a compass and a straightedge.
We need a circle to construct an isosceles trapezoid inscribed in a circle. Therefore, we should first construct a circle. Let's mark point O on our paper.
Now we can construct a circle with center at O using a compass.
Next we will draw a diameter by using a straightedge to have the bottom side of the trapezoid.
We will next set compass width to BO.
Let's draw two arcs with this compass setting. We will first put the compass point on point A and draw an arc intersecting ⊙ O.
We can follow the same process for point B.
Finally, we can connect these points using a straightedge.
Based on our construction, we can order the steps.
Which of the following polygons can be constructed out of a construction of a hexagon inscribed in a circle?
Let's consider a hexagon inscribed in a circle.
If we overlap this construction with given polygons one by one, there are only two polygons that would fit it. Let's connect the points B, C, E, and F.
We can construct the given rectangle. Next, we will connect the points A, C, and E.
We can also construct the equilateral triangle. However, there is no way to construct the isosceles triangle and the pentagon out of the construction of a hexagon. Therefore, the possible options are B and C.