Pearson Geometry Common Core, 2011
PG
Pearson Geometry Common Core, 2011 View details
1. The Pythagorean Theorem and Its Converse
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Exercise 58 Page 498

Find the scale factor that takes rectangle ABCD to rectangle EFGH.

2.25

Practice makes perfect

Let's draw the similar rectangles, one with a side AB=4 and another with corresponding side EF=6. To work with the areas, we need to know two adjacent sides of the rectangles. Therefore, to get the adjacent side of rectangle ABCD we can use an arbitrary value and let AD=a.

If we are going to compare the areas to determine how much larger rectangle EFGH is, we need to express EH in terms of a as well. To do this, we need to find the scale factor.

Scale Factor: r=AB/EH=6/4=1.5 With this scale factor, we know that EH=1.5a. This also means that we can find the areas of the two rectangles.

Now let's look at the ratio of the areas of the rectangles.
A_(EFGH)/A_(ABCD)
6(1.5a)/4a
9a/4a
2.25
Therefore, rectangle EFGH is 2.25 times larger than rectangle ABCD.

Alternative Solution

Using Ratios of Similarity

When looking at different dimensions of similar figures, we need to adjust the ratio to the type of measurement.

Measurement Ratio
Length a:b
Area a^2:b^2
Volume a^3:b^3

Notice that we are given a unit of length for each of two similar rectangles. Let's fill those values into our table using the larger rectangle's length first. We need to find the ratio for the area.

Measurement Ratio a=6 and b=4
Length a:b 6:4
Area a^2:b^2 6^2:4^2
Recall ratios are fractions. Let's simplify the ratio to get our multiplier.
6^2:4^2
â–Ľ
Simplify
36:16
36/16
9/4
Therefore, the area of DEFG is 94 or 2.25 times greater than the area of ABCD.