Pearson Geometry Common Core, 2011
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Pearson Geometry Common Core, 2011 View details
5. Law of Sines
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Exercise 8 Page 525

The Law of Sines relates the sine of each angle to the length of the opposite side.

x=19.1 and y=14.5

Practice makes perfect

For any △ ABC, let the lengths of the sides opposite to angles A, B, and C be a, b, and c, respectively.

The Law of Sines relates the sine of each angle to the length of the opposite side. sin A/a=sin B/b=sin C/c

Let's use this law to find the values of x and y. We will find them one at a time.

Finding x

Consider the given triangle.

We know that the length of a side is 18 and that the measure of its opposite angle is 63^(∘). We also know that the measure of the angle that is opposite to the side we want to find is 71^(∘). With this information and using the Law of Sines, we can write an equation in terms of x. sin 63^(∘)/18=sin 71^(∘)/x Let's solve our equation!
sin 63^(∘)/18=sin 71^(∘)/x
sin 63^(∘)* x=sin 71^(∘)* 18
x=sin 71^(∘)*18/sin 63^(∘)
x=19.101245...
x=19.1

Finding y

We can find the third interior angle using the Triangle Angle Sum Theorem. ∠ B=180^(∘)- 63^(∘)- 71^(∘) ⇕ ∠ B= 46^(∘) Consider the triangle with the new information.

We know that the length of a side is 18 and that the measure of its opposite angle is 63^(∘). We want to find the length of the side that is opposite to the angle whose measure is 46^(∘). We can use the Law of Sines again! sin 63^(∘)/18=sin 46^(∘)/y Let's solve the above equation for y using the Cross Product Property.
sin 63^(∘)/18=sin 46^(∘)/y
sin 63^(∘)* y=sin 46^(∘)* 18
y=sin 46^(∘)*18/sin 63^(∘)
y=14.532010...
y=14.5