Pearson Geometry Common Core, 2011
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Pearson Geometry Common Core, 2011 View details
Chapter Test
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Exercise 18 Page 425

The given figure is a parallelogram, so both pairs of opposite sides are parallel.

Coordinates of S: (0,0)
Coordinates of T: (c+b,d)
Midpoint of ST: ( c+d2, d2 )
Slope of ST: dc+b

Practice makes perfect

Let's begin by determining the coordinates of S and T. Then, we can find the midpoint and the slope of ST.

Coordinates of S and T

First, notice that S is the origin. Therefore, its coordinates are (0,0). As arbitrary placeholders, let's label the coordinates of T as (x,y). We can call the other two points R and Q.

We know that the given figure is a parallelogram, so both pairs of opposite sides are parallel. Let's find the slopes of the sides by substituting the coordinates of the points into the Slope Formula.

Side Slope Formula Simplify
SR d-0/c-0 d/c
RT y-d/x-c y-d/x-c
TQ 0-y/b-x y/b-x
QS 0-0/b-0 0

Now we can use logic to find the values of x and y in terms of the given variables. Since RT and QS are parallel, their slopes must be equal. y-dx-c= 0 In order for this fraction to equal 0, the numerator must be 0. y-d=0 ⇔ y= d Now we know that the y -coordinate of T is d. Since SR and TQ are parallel, their slopes are also equal. Additionally, we can replace the y with d in the slope of TQ. d/c= y/x-b ⇔ d/c= d/x-b Because the numerators are now the same, these slopes will be equal only if the denominators are equal. c=x-b ⇔ x= c+b This tells us the x-coordinate of T. Finally, we have that the coordinates of point T are ( c+b, d).

Midpoint

To find the midpoint of ST, we can substitute the coordinates of S and T in the Midpoint Formula.
( x_1+x_2/2, y_1+y_2/2 )
( 0+ c+d/2, 0+ d/2 )
( c+d/2, d/2 )
The coordinates of the midpoint are ( c+d2, d2).

Slope

Now, let's find the slope of ST. To do so, we will substitute the coordinates of S and T into the Slope Formula.
m = y_2-y_1/x_2-x_1
m=d- 0/c+b- 0
m=d/c+b
The slope of ST is dc+b.