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Calculate the relative frequencies for one day of the blood drive. Then make a new table of frequencies for two days of the blood drive, and calculate new relative frequencies.
No. See solution.
The honor society at a local high school sponsors a blood drive. The given table indicates the frequency of each donor blood type after one day of the blood drive.
Blood Type | Frequency for One Day |
---|---|
O | 30 |
A | 25 |
B | 6 |
AB | 2 |
Let's add a column to our table representing the relative frequencies for each blood type after one day of the blood drive.
Blood Type | Frequency for One Day | Relative Frequency |
---|---|---|
O | 30 | 30/63=10/21 |
A | 25 | 25/63 |
B | 6 | 6/63=2/21 |
AB | 2 | 2/63 |
Now let's consider the fact that after the second day of the blood drive, the frequencies for all blood types double. We can use this fact to make the frequency table for the two-day long blood drive.
Blood Type | Frequency for Two Days |
---|---|
O | 30 * 2=60 |
A | 25* 2=50 |
B | 6* 2=12 |
AB | 2* 2=4 |
To calculate the relative frequencies for this data, we need to calculate the total once again. Total for two days: 60+50+12+4= 126 Note that this is twice as much as the total after one day, because if we double all the frequencies then their sum also gets doubled. We can now calculate the relative frequencies for each blood type after two days of the blood drive.
Blood Type | Frequency for Two Days | Relative Frequency |
---|---|---|
O | 60 | 60/126=10/21 |
A | 50 | 50/126=25/63 |
B | 12 | 12/126=2/21 |
AB | 4 | 4/126=2/63 |
Finally, we can compare the obtained relative frequencies to see if they changed.
Blood Type | Relative Frequency for One Day | Relative Frequency for Two Days | Equal? |
---|---|---|---|
O | 10/21 | 10/21 | Yes |
A | 25/63 | 25/63 | Yes |
B | 2/21 | 2/21 | Yes |
AB | 2/63 | 2/63 | Yes |
The relative frequencies did not change. Note that when we multiplied each frequency by 2 the total of the frequencies also were multiplied by 2. Therefore, when we calculated the relative frequencies for two days we had doubled the numerator divided by the doubled denominator. This allowed us to reduce the fraction and gave the same result as before.