Pearson Geometry Common Core, 2011
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Pearson Geometry Common Core, 2011 View details
3. Permutations and Combinations
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Exercise 15 Page 841

Recall the formula for a combination, _n C_r = n!/r!(n-r)!.

210

Practice makes perfect
To evaluate the given combination, we will use the corresponding formula. _n C_r = n!/r!(n-r)! We are given that n=10 and r=6. Let's substitute these values into the formula.
_n C_r = n!/r!(n-r)!
_(10) C_6 = 10!/6!( 10- 6)!
_(10) C_6 = 10!/6!4!

Write as a product

_(10) C_6 = 10* 9* 8* 7* 6* 5* 4* 3* 2* 1/(6* 5* 4* 3* 2* 1)(4* 3* 2* 1)
_(10) C_6 = 10* 9* 8* 7* 6* 5* 4* 3* 2* 1/(6* 5* 4* 3* 2* 1)(4* 3* 2* 1)
_(10) C_6 = 10* 9* 8* 7/4* 3* 2* 1
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Simplify
_(10) C_6 = 10* 3* 3* 4* 2* 7/4* 3* 2* 1
_(10) C_6 = 10* 3* 3* 4* 2* 7/4* 3* 2* 1
_(10) C_6 = 10* 3* 7/1
_(10) C_6 = 10* 3* 7
_(10) C_6 = 210
There are 210 combinations.

Alternative Solution

Using the calculator

We can evaluate the number of combinations _(10)C_6 by using the graphic calculator. To do so, we have to start by entering the number of items, which is equal to 10.

window of a TI83 graphing calculator

Next, we push MATH and scroll right until we reach PRB. Then, we scroll down to the third row and push ENTER.

window of a TI83 graphing calculator
window of a TI83 graphing calculator

Finally, by entering the number of items to be chosen and hitting ENTER, we can calculate the number of combinations.

window of a graphing calculator