Pearson Geometry Common Core, 2011
PG
Pearson Geometry Common Core, 2011 View details
3. Permutations and Combinations
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Exercise 17 Page 841

Practice makes perfect
a We want to find the number of 3-student committees we can form out of a class of 30 students. Note that the order we choose the students in is not important since 3 students are in the committee, no matter the order they were chosen in. Since the order is not important, let's use combinations.
_nC_r = n!/r! (n-r)! The formula for the number of combinations of n objects taken r at a time, for 0 ≤ r ≤ n. In our case, we are choosing from the class of 30 students, so n = 30. Out of these, we choose exactly 3 students to form the committee, so r = 3. Let's substitute these values into the formula.
_nC_r = n!/r! (n-r)!
_(30) C_3 = 30!/3!( 30- 3)!
â–Ľ
Evaluate right-hand side
_(30)C_3 = 30!/3! 27!

Write as a product

_(30)C_3 = 30 * 29 * 28 * 27 * 26 * 25 * ... * 2 * 1/( 3 * 2 * 1 ) ( 27 * 26 * 25 * ... * 2 * 1)
_(30)C_3 = 30 * 29 * 28 * 27 * 26 * 25 * ... * 2 * 1/( 3 * 2 * 1 ) ( 27 * 26 * 25 * ... * 2 * 1)
_(30)C_3 = 30 * 29 * 28/3 * 2 * 1
_(30)C_3 = 24 360/6
_(30)C_3 = 4060
The committee can be formed in 4060 different ways.

Alternative Solution

Using a Calculator

We can evaluate the number of combinations _(30)C_3 using a graphing calculator. To do so, we have to start by entering the total number of students, 30.

window of a TI83 graphing calculator

Next, we push MATH and then scroll right until we reach PRB. Then, scroll down to the third row and push ENTER.

window of a TI83 graphing calculator
window of a TI83 graphing calculator

Finally, by entering the number of students to be chosen and hitting ENTER, we can calculate the desired number of combinations.

window of a graphing calculator
b This time we want to find the number of different ways we can form a committee of 5 students. We will use the same formula as in Part A.
_nC_r = n!/r! (n-r)! In this case, we will substitute 5 for r. The value of n remains the same as in Part A, 30.
_nC_r = n!/r! (n-r)!
_(30) C_5 = 30!/5!( 30- 5)!
â–Ľ
Evaluate right-hand side
_(30)C_5 = 30!/5! 25!

Write as a product

_(30)C_5 = 30 * 29 * 28 * 27 * 26 * 25 * 24 * ... * 2 * 1/( 5 * 4 * 3 * 2 * 1 ) ( 25 * 24 * ... * 2 * 1)
_(30)C_5 = 30 * 29 * 28 * 27 * 26 * 25 * 24 * ... * 2 * 1/( 5 * 4 * 3 * 2 * 1 ) ( 25 * 24 * ... * 2 * 1)
_(30)C_5 = 30 * 29 * 28 * 27 * 26/5 * 4 * 3 * 2 * 1
_(30)C_5 = 17 100 720/120
_(30)C_5 = 142 506
There are 142 506 different ways the committee of 5 students can be formed.

Alternative Solution

Using a Calculator

We can evaluate the number of combinations _(30)C_5 using a graphing calculator. To do so, we have to start by entering the total number of students, 30.

window of a TI83 graphing calculator

Next, we push MATH and then scroll right until we reach PRB. Then, scroll down to the third row and push ENTER.

window of a TI83 graphing calculator
window of a TI83 graphing calculator

Finally, by entering the number of students to be chosen and hitting ENTER, we can calculate the desired number of combinations.

window of a graphing calculator