Pearson Geometry Common Core, 2011
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Pearson Geometry Common Core, 2011 View details
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Exercise 35 Page 873

Note that in this case we need to use conditional probability. The expression P(B|A) means the probability of event B occurring given that event A has occurred.

5574, or about 74.3 %

Practice makes perfect
We are told that at a shoe store yesterday 74 % of customers bought shoes, 38 % bought accessories, and 55 % bought both shoes and accessories. We want to find the probability of randomly selecting a customer who bought accessories given that they bought shoes. Note that in this case we need to use conditional probability. P(B|A)=P(AandB)/P(A) The expression P(B|A) means the probability of event B occurring given that event A has occurred. In our case event B will be buying accessories by a customer, which we will mark as A. Event A will be buying shoes, which we will mark as S. P( A| S)=P( S and A)/P( S) We know that 55 % of customers bought both shoes and accessories, so the probability that a customer who bought both items is selected is 55 %= 0.55. Also, 74 % of customers bought shoes. This means that the probability of selecting a customer who bought shoes is 74 %= 0.74. P(SandA)=& 0.55 P(S)=& 0.74 Let's substitute these values into our expression and find the conditional probability!
P(A|S)=P(SandA)/P(S)
P(A|S)=0.55/0.74
P(A|S)=55/74
We can also express this probability as a percentage. Remember that 0.01=1 %.
P(A|S)=55/74
Convert to percent
P(A|S)=0.743243...
P(A|S)≈ 0.743
P(A|S)≈ 74.3 %
The probability of selecting a customer who bought accessories given that they bought shoes is 5574, or about 74.3 %.