Pearson Geometry Common Core, 2011
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Pearson Geometry Common Core, 2011 View details
5. Volumes of Pyramids and Cones
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Exercise 24 Page 731

Use the formula for the volume of a pyramid.

312cm^3

Practice makes perfect

The given figure is a pyramid.

To calculate the volume of a pyramid, we can use a known formula where B is the area of the base and h is the height. V=1/3Bh We know that the base of the pyramid is an equilateral triangle with the side length of 12 cm. To find the area of this triangle, we need to find its height. Recall that the height in an equilateral triangle height divides the triangle into two congruent 30^(∘)-60^(∘)-90^(∘) triangles.

Notice that, in a 30^(∘)-60^(∘)-90^(∘) triangle, the longer leg is sqrt(3) times the shorter leg. Therefore, the height of the base will be 6sqrt(3). Now we have everything to calculate the area of the base. Let's use the formula for the area of a triangle!
B = 1/2( 12)( 6sqrt(3))
B = 1/2(72sqrt(3))
B=72sqrt(3)/2
B=36sqrt(3)
The area of the base equals 36sqrt(3)cm^2 and we are given that the height is 15cm. Let's substitute these values into the formula and calculate V.
V=1/3Bh
V=1/3( 36sqrt(3))( 15)
Simplify right-hand side
V=1/3(540sqrt(3))
V=540sqrt(3)/3
V=180sqrt(3)
V=311.769145...
V≈ 312
The volume of the pyramid is approximately 312 cubic centimeters.