1. Areas of Parallelograms and Triangles
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Use the Triangle Inequality Theorem.
No, see solution.
XY+XZ>YZ XZ+YZ>XY YZ+XY>XZ Applying this theorem to the given side lengths, we have three inequalities. I:6+4? >11 & ⇒ 10 ≯ 11 II:4+11? >6 & ⇒ 15 > 6 III:11+6? >4 & ⇒ 17 > 4 Since Inequality I is not true, a triangle cannot have these sides.