One combination of numbers that you can use as base and height is 6 and 4. You can use the fact that parallel lines are equidistant.
See solution.
Practice makes perfect
We need to draw three triangles with an area of 12 units^2. Let's begin by remembering the formula to find the area of a triangle with base b and height h.
A = b* h/2
Since the area is equal to 12, then b* h=24. There are several combinations of numbers that can satisfy this. However, we will fix each length. For example, let b=6 and h=4. Then, on a graph paper, let's draw a segment with a length of 6 units.
Next, we will draw a line parallel to the segment we draw above such that the distance between them is equal to 4 units.
We now choose an arbitrary point P on the line drawn and connect it with the A and B to form a triangle.
The triangle ABP is an acute triangle with area 12 units^2. Let's repeat the process again, but this time we will pick a point Q on the line such that it is directly above A.
We have that â–³ ABQ is a right triangle with area 12 units^2. Finally, let's pick a point R so that it is not above AB.
As we can see, â–³ ABR is an obtuse triangle with an area of 12 units^2. Keep in mind that there are infinitely many ways of drawing the required triangles, so your answer may vary.
