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Pearson Geometry Common Core, 2011

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Pearson Geometry Common Core, 2011 View details

3. Measuring Segments

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Exercise 20 Page 24

Lines PT and TQ are congruent.

PT = 33

Practice makes perfect

We know that PT is congruent to TQ because they have matching tick-marks.

Since PT and TQ are congruent, the expressions for their lengths must be equal. We can set the two expressions equal to one another and solve for x.

5x+3=7x-9

LHS-7x=RHS-7x

- 2x+3= - 9

LHS-3=RHS-3

- 2 x= - 12

.LHS /(- 2).=.RHS /(- 2).

x=6

The length of PT is given by 5x+3. We can substitute 6 for x to find PT.

PT=5x+3

x= 6

PT=5( 6)+3

Multiply

PT=30+3

Add terms

PT=33

Subchapter links

Lesson Check p.23

Practice and Problem-Solving Exercises p.24-25

Standardized Test Prep p.26

Mixed Review p.26