Pearson Algebra 1 Common Core, 2011
PA
Pearson Algebra 1 Common Core, 2011 View details
2. Multiplying and Factoring
Continue to next subchapter

Exercise 27 Page 495

The area of the frame is the area of the entire square expect for the area of the circular mirror.

25x^2(9-Ď€)

Practice makes perfect

Let's draw the mirror described in the exercise.

We are asked to calculate the area of the metal frame. We can see that the area of the frame is the area of the entire square, F, minus the area of the circular mirror, M. Let's calculate the area of the entire square first. Recall the formula for the area of a square. A=s^2Here, s is the side length of the square. In our case s= 15x.
F=s^2
F=( 15x)^2
F=15^2x^2
F=225x^2
Next we will calculate the area of the circular mirror. Recall the formula for the area of a circle. A=Ď€ r^2 Here, r is the radius of the circle. In our case r= 5x.
M=Ď€ r^2
M=Ď€ ( 5x)^2
â–Ľ
Simplify
M=Ď€* 5^2x^2
M=Ď€* 25x^2
M=25Ď€ x^2
As we have mentioned before, the area of the frame A is equal to the area F minus the area M. A=F-M=225x^2-25Ď€ x^2 We have to rewrite our answer in factored form. Let's find the Greatest Common Factor (GCF) of the expression. To do so, we will factor each term in the expression. 225x^2=&3* 3* 5* 5* x* x 25Ď€ x^2=& 5* 5*Ď€* x* x The GCF is 5* 5* x* x, or 25x^2. Finally, we will factor out the GCF.
225x^2-25Ď€ x^2
â–Ľ
Factor out 25x^2
25x^2* 9-25Ď€ x^2
25x^2* 9-25x^2*Ď€
25x^2(9-Ď€)
The factored form of the area of the metal frame is 25x^2(9-Ď€).