body{margin:0;} noscript{z-index: 10000; position: fixed; display: block; height: 100%; width: 100%; background: #fff;} noscript .fa{font-size: 40px; display:block; color: #daa520;} noscript div{margin-top: 6%; padding-left: 20px; padding-right: 20px; text-align: center;} ! You must have JavaScript enabled to use this site.

Pearson Algebra 1 Common Core, 2011

PA

Pearson Algebra 1 Common Core, 2011 View details

5. Rational Exponents and Radicals

Continue to next subchapter

Exercise 69 Page 452

You will need to apply the Properties of Equality, solving until the equation is in standard form.

6x-3y=-17

Practice makes perfect

Equations in standard form are written in a specific format. Ax+ By= CIn this form, A, B, and C are integers. Besides, A and B cannot both be zero. We will use the Properties of Equality to rewrite the given equation in this form.

3y-5=6(x+2)

Distribute 6

3y-5=6x+12

LHS+5=RHS+5

3y=6x+17

LHS-6x=RHS-6x

3y-6x=17

CommutativePropAdd

Commutative Property of Addition

- 6x+3y=17

LHS * (- 1)=RHS* (- 1)

6x-3y=-17

Below we compare this result with the general standard form equation. Ax+ By&= C 6x - 3y&= -17

Subchapter links

Lesson Check p.450

Practice and Problem-Solving Exercises p.450-452

Standardized Test Prep p.452