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Pearson Algebra 1 Common Core, 2011
PA
Pearson Algebra 1 Common Core, 2011 View details
5. Rational Exponents and Radicals
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Exercise 69 Page 452

You will need to apply the Properties of Equality, solving until the equation is in standard form.

6x-3y=-17

Practice makes perfect

Equations in standard form are written in a specific format. Ax+ By= CIn this form, A, B, and C are integers. Besides, A and B cannot both be zero. We will use the Properties of Equality to rewrite the given equation in this form.

3y-5=6(x+2)
Distr

Distribute 6

3y-5=6x+12
AddEqn

LHS+5=RHS+5

3y=6x+17
SubEqn

LHS-6x=RHS-6x

3y-6x=17
CommutativePropAdd

Commutative Property of Addition

- 6x+3y=17
MultEqn

LHS * (- 1)=RHS* (- 1)

6x-3y=-17

Below we compare this result with the general standard form equation. Ax+ By&= C 6x - 3y&= -17

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arrow_right Lesson Check p.450
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arrow_right Practice and Problem-Solving Exercises p.450-452
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arrow_right Standardized Test Prep p.452
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arrow_right Mixed Review p.452
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