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Pearson Algebra 1 Common Core, 2011
PA
Pearson Algebra 1 Common Core, 2011 View details
5. Rational Exponents and Radicals
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Exercise 68 Page 452

You will need to apply the Properties of Equality, solving until the equation is in standard form.

7x+6y=12

Practice makes perfect

Equations in standard form are written in a specific format. Ax+ By= CIn this form, A, B, and C are integers. Besides, A and B cannot both be zero. We will use the Properties of Equality to rewrite the given equation in this form.

- 3y+6=7x/2
MultEqn

LHS * 2=RHS* 2

2(- 3y+6)=7x
Distr

Distribute 2

- 6y+12=7x
AddEqn

LHS+6y=RHS+6y

12=7x+6y
RearrangeEqn

Rearrange equation

7x+6y=12

Below we compare this result with the general standard form equation. Ax+ By&= C 7x+ 6y&= 12

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arrow_right Lesson Check p.450
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arrow_right Practice and Problem-Solving Exercises p.450-452
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arrow_right Standardized Test Prep p.452
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arrow_right Mixed Review p.452
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