Sign In
Recall and implement two different forms of the line equation.
See solution.
Suppose that we have the graph shown below.
Using this example graph, we will illustrate two methods to find the equation of a line given its graph.
One way is to use the point-slope form.
In our example, we identify the point (0,1). We can see that when the run is 2 we have a rise of 3 units. Let's calculate the slope.
Now we substitute the found values into the point-slope form to get our line equation.
Substitute values
Distribute 1.5
LHS+1=RHS+1
The corresponding line equation for the example graph is y= 1.5 x +1.
We can also find the line equation using the slope-intercept form. y = mx + b Here m is the slope of the line and b is the y-intercept. Once again, let's start by identifying these features in the graph.
We now proceed to calculate the slope, just as we did above. We will not show that again, and we will just use its value — m=1.5. We can see from the graph that in this case, b=1. If we substitute these values into the slope-intercept form, we will find our line equation. y = 1.5x + 1