Recall the point-slope form, where m is the slope and the point ( x_1, y_1) lies on the graph of the line.
y- y_1= m(x- x_1)
Observing the given equation, we can see that it would only take a small adjustment for it to be in point-slope form.
y+3=1/2(x+2)
a+b=a-(- b)
y-(-3)=1/2(x-(-2))
Let's highlight the slope m and the coordinates of the point ( x_1, y_1).
y-( -3) &= 1/2(x-( -2))
We have that the slope of the given line is 12 and that the line passes through the point ( - 2, - 3). To graph the line, we will plot the point (-2,- 3), then use the slope of 12 to move one step up and two steps to the right. By connecting the first point and our new point with a line, we get the graph of the equation.
