Exercise 20 Page 321

Let's recall the point-slope form, where m is the slope, and the point ( x_1, y_1) lies on the graph of the line. y- y_1= m(x- x_1)We are given the point ( 4, 0), through which the line passes, and the slope 4, so we have everything we need to create a point-slope form equation.

y-y_1=m(x-x_1)

SubstituteIII

Substitute x_1= 4,y_1= 0,m= 4

y- 0= 4(x- 4)

SubTerm

Subtract term

y=4(x-4)

We have found the point-slope form equation of the line. y=4(x-4)