Pearson Algebra 1 Common Core, 2011
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Pearson Algebra 1 Common Core, 2011 View details
3. Measures of Central Tendency and Dispersion
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Exercise 21 Page 743

How do you find the mean of a data set? The median?

Student A has a greater mean and a greater median.

Practice makes perfect

To find which data set has a greater mean and a greater median, we will find each of these measures for each data set. Let's start with the data set of Student A.

Student A

Let's look at the given graph.

To find the mean of the data set we will add each value and divide the sum by 30, because there are 30 values in the data set. Let's do it!
Mean= 2(30) + 4(31) + 5(32) + 5(33) + 6(34) + 8(35)/30
Mean= 993/30
Mean= 33.1
Now we know that the mean of the data set of Student A is 33.1. To find the median we will list every element of the data set. Then, we will identify the values in the middle. Let's list the values. &30, 30, 31, 31, 31, 31, 32, 32, 32, 32, &32, 33, 33, 33, 33, 33, 34, 34, 34, 34, &34, 34, 35, 35, 35, 35, 35, 35, 35, 35 Now we can find the median by calculating the average of the middle values.
Median= 33 + 33/2
Median= 66/2
Median= 33
The median of the data set of Student A is 33.

Student B

Let's look at the given graph.

To find the mean of the data set we will add each value and divide the sum by 30, because there are 30 values in the data set. Let's do it!
Mean=6(30) + 8(31) + 7(32) + 6(33) + 3(34)/30
Mean=952/30
Mean= 31.733333...
Mean= 31.7
Now we know that the mean of the data set of Student B is about 31.7. To find the median we will list every element of the data set. Then we will identify the values in the middle. Let's list the values. &30, 30, 30, 30, 30, 30, 31, 31, 31, 31, &31, 31, 31, 31, 32, 32, 32, 32, 32, 32, &32, 33, 33, 33, 33, 33, 33, 34, 34, 34 Now we can find the median by calculating the average of the middle values.
Median= 32 + 32/2
Median= 64/2
Median= 32
The median of the data set of Student B is 32.

Conclusion

We can see that Student A has a mean of 33.1 and a median of 33. On the other side, Student B has a mean of 31.7 and a median of 32. Therefore, Student A has a greater mean and a greater median than Student B.